Find the instantaneous velocity (cont.1)

When delta t = 0.1 s , t2= 1.1 s and

x2 = 20m +(5.0 m/s^2)(1.1 s)^2 = 26.5 m.
The average velocity during this interval is

Vav =(26.05 m- 25 m)/(1.1 s – 1.0 s)
= 10.5 m/s

When delta t = 0.01 s , t2= 1.01 s and

x2 = 20m +(5.0 m/s^2)(1.01 s)^2 = 25.1005 m.
The average velocity during this interval is

Vav =(25.1005 m- 25 m)/(1.01 s – 1.0 s)

= 10.05 m/s


When delta t = 0.001 s , t2= 1.001 s and

x2 = 20m +(5.0 m/s^2)(1.001 s)^2 = 25.010005 m
The average velocity during this interval is

Vav =(25.010005 m- 25 m)/(1.001 s – 1.0 s)

= 10.005 m/s

As delta t get smaller and smaller, the average velocity gets closer and closer to 10 m.0 m/s, and we conclude that the instantaneous velocity at time t =1.0 is 10. m/s.

Answer

Next : Derive a general expression fot the instantaneous velocity